Limiting Reagent Worksheet 1 Answers
Limiting Reagent Worksheet #1
ane. Given the following reaction: (Balance the equation get-go!)
C iii H 8 + five O 2 -------> iii CO 2 + 4H 2 O
a) If you start with fourteen.8 thousand of C three H 8 and 3.44 g of O 2 , determine the limiting reagent
14.8 thousand C 3 H 8 x x x = 24.2 grand H 2 O
1 mol C 3H8
44.09 g C 3Hviii
iv mol H twoO
i mol C 3H eight one mol H iiO
18.02 g H 2O
iii.44 yard O 2 x 10 x = 1.55 grand H ii O
32yardO2
1 mol Otwo
v mol O2
4 mol H twoO
i mol H 2O
18.02 g H 2O
O two is limitng
b) determine the number of moles of carbon dioxide produced
3.44 g O 2 x x x = 2.84 g H 2 O
321000Otwo
i mol Otwo
five mol Oii
three mol CO 2
1 mol CO 2
44.01 g CO 2
c) determine the number of grams of H 2 O produced
1.55 thousand H2O
d) determine the number of grams of excess reagent left
3.44 g O two x x x = .0948 g C three H 8 used
32gO2
ane mol O2
5 mol O2
one mol C 3H8
1 mol C 3H8
44.09m C 3H 8
14.8g C iii H 8 - 0.948g C 3 H viii = 13.9g C three H 8 remain
ii. Given the following equation:
Al 2 (So three ) 3 + vi NaOH ------> 3 Na 2 And then 3 + 2 Al(OH) iii
a) If 10.0 chiliad of Al 2 (SO 3 ) 3 is reacted with x.0 one thousand of NaOH, determine the limiting
reagent
x.00 g Al 2 (Then three ) 3 x x x = 12.9g Na 2 And then four
i mol Al 2(SO iii)3
294.171000 Al 2(SO3)three
3 mol N a 2SouthwardOfour
1 mol Al 2(SouthwardO three)3 1 mol N a 2SO4
126.05 g Na 2SO 4
10.00 g Na 2 SO four 10 x x = 15.8g Na two Then 4
1 mol N aOH
294.17g NaOH 6 mol N aOH
3 mol N a 2SouthwardOfour
1 mol N a 2SouthO4
126.05 chiliad Northwarda 2SouthwardO 4
Limiting Reagent Worksheet 1 Answers,
Source: https://www.studocu.com/en-us/document/stony-brook-university/general-chemistry-ii/limiting-reagent-worksheet-1-and-2/27295784
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